Question

The length of time it takes college students to find a parking spot in the library parking lot follows a normal distribution with a mean of 5.5 minutes and a standard deviation of 1 minute. Find the probability that a randomly selected college student will find a parking spot in the library parking lot in less than 5 minutes. O 0.3085 O 0.3551 O 0.2674 O 0.1915

Answer 1

Solution :

Given that ,

mean = $\mu$ = 5.5

standard deviation = $\sigma$ = 1   

P(X<5 ) = P[(X- $\mu$ ) / $\sigma$ < (5 - 5.5) /1 ]

= P(z <-0.5 )

Using z table

= 0.3085

probability=0.3085