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a) [6 marks] Suppose a group of 900 smokers (who all wanted to quit smoking) were randomly assigned to receive an antidepress
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Answer #1

Answer:

Given,

sample proportion p1^ = x1/n1 = 23/148 = 0.16

p2^ = x2/n2 = 97/752 = 0.13

p = (x1+x2)/(n1+n2) = (23+97)/(148+752) = 0.133

Ho : p1 - p2 = 0

Ha : p1 - p2 != 0

test statistic z = (p1^ - p2^)/sqrt(p(1-p)(1/n1 + 1/n2))

substitute values

= (0.16 - 0.13)/sqrt(0.133(1-0.133)(1/148 + 1/752))

= 0.98

P value = 0.3270861 [since from z table]

= 0.3271

Here p value > alpha, so we fail to reject Ho.

So there is no sufficient evidence to support the claim.

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