3) For the given system restrict attention to the first quadrant, (x, y = 0). dx...
(5 points) Find all 5 equilibria for the system of first order ODES dx = x(4-y-12) dt dy = y(x2-1) dt
In Problems 3-6, find the critical point set for the given system. dx 4. dx = x-y, 3. dt y1 dt dy dy = x2 y2 - 1 dt = x + y + 5 dt dx dx x2- 2xy y2- 3y 2 6. 5. dt dt dy dy 3xy - y2 (x- 1)(y 2) dt dt
Classify the critical point (0, 0) of the given linear system. Draw a phase portrait. dx/df 3x+ y a. dx/dt -x+ 2y dx/dt =-x +3y dy/dt -2x + y dy/dt x+ y Classify the stationary point (0, 0) of the given linear system. Draw a phase portrait. dy/dt -x+y b. dx/dt =-2x-y dx/dt-2x +5/7 y dx/dt 3x-y dx/dt 3x dy/dt 3x- y dy/dt 7x- 3y dy/dt x+y dy/dt 3y
Find dy/dt using the given values. y = x - 4x for x = 3, dx/dt = 2. y = [ X dt . dx/dt = 2. Enter an exact number
Solve the given initial value problem. x(0) = 1 dx = 4x +y- e 3t, dt dy = 2x + 3y; dt y(0) = -3 The solution is X(t) = and y(t) =
Assume that x and y are functions of t, and x and y are related by the equation y= 4x+3. (a) Given that dx/dt=1, find dy/dt when x=2. (b) Given that dy/dt=4, find dx/dt when x=3.
hw help
Consider the equation exin(y)+5x +1=y? Find dy dx in terms of X and y. Evaluate dx at (x,y) = (0,1). Select the correct answer. -5 5 ООО 2 Suppose that 3 xy2 = x²y + y2 + 14. dy Use implicit differentiation to find an expression for in terms of both X and y. dx dy Now give the value of when x = 3 and y = 2 dx -36 13 3 0 24 41 о ....
4. Solve the given system of equations. (10 points each) dx dy 6- + dt + 3y = 0 dt dx dt + 4x - y = 0
Consider the following system:
dx/dt=y(x^2+y^2-1)
dy/dt= -x(x^2 +y^2-1)
Find the equilibrium solution.
13. Consider the following system dx dy (e) Find the equilibrium solutions (0 Use Maple to sketch a phase portrait (me to understand the qualitative behavior of
13. Consider the following system dx dy (e) Find the equilibrium solutions (0 Use Maple to sketch a phase portrait (me to understand the qualitative behavior of
Solve the system of differential equations dx/dt = x-y, dy/dt = 2x+y subject to the initial conditions x(0)= 0 and y(0) = 1.