Question

Jim is timed 16 times to measure his performance in minutes of a certain task. The...

Jim is timed 16 times to measure his performance in minutes of a certain task. The average of these 16 observations came out to be 8.5 minutes with a standard deviation of 1.25 minutes. Obtain a 90% confidence interval for the actual mean performance of Jack's work.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution :

Given that,

t\alpha /2,df = 1.753

Margin of error = E = t\alpha/2,df * (s /\sqrtn)

= 1.753 * (1.25 / \sqrt 16)

Margin of error = E = 0.55

The 90% confidence interval estimate of the population mean is,

\bar x - E < \mu < \bar x + E

8.5 - 0.55 < \mu < 8.5 + 0.55

7.95 < \mu < 9.05

(7.95 , 9.05)

Add a comment
Know the answer?
Add Answer to:
Jim is timed 16 times to measure his performance in minutes of a certain task. The...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT