Question

Question 4: For the Figure below determine the location of the centroid (x,y). 150 mm 150 mm 100 mm 100 mm 250 mm 85 mm

Answer 1

प 150mm 150mm 100 mm 100 mm 거 250 mm Area of 1= A1= ź x 250x (100+100) = 250x200 2 = 25000 mm Forg Centroid Xi = 2x2500 from Yanis wil 500 3 100+100 2010 from x-anis } = h 3 Area (A2) = 200x300 1 x (85)2 (Area of rectangle - Area of Girele) bxh fd2 60000 – 5674.57 54325,5 mm M2 150+250= 400mm (from Y-an18) 필 100 mm from x-anis 25000 x 500 + 54325,5 x 400 = Aisti + Azha AITAZ 3 2 5000+ 54325.5 326.463 mm Ý = A. G + Azt 25000 x 200 3 + 54325,5 x 100 Ait Az 25000+ 543 2505 89.494 mm

Qn3 ya 36mm 108mm 0 K 24 mm 400mm 2 3 48 mm 10,0) 150mm X tehar no Taking the X andy anis as shown in figure for Area = Al- 108 x 36 mm² = 38.88 mm² rose st, = 108 - 54 mm mi = (400-367+ 36 mm 382 mm for ② Area 2 = A 2 = (400-98-36) x 24 mm² = 7584 mm2 M2 = (108-24) + 24 mm = 96mm I = 48+ 400-36-48) mm - 200mm for ③ Az = 48x 150 mm2 - 1200 mm nz (108-24 ) + 150 mm = 159 mm 48 mm = 24mm

ART & A202 + Ana Ait Azt A3 3888 X 54+ 7584x 96 + 7200X 159 3888 + 7584 + 7200 - lll.53 5mm Allt A₂Yz TA3Y3 Ai+Azt A3 3888 X 382 + 7584x 206+ 7200x24 3888 + 7584 + 7200 = 152 mm my o.sinlo.sin On 2 5,5in 1.5in lin x K2.5in* 2.5 int Que to Symmetry n will be a o. AL = (2.5+2.5) x1 = 5 in Y = √ = 0.5 in A2 = x (2.5-0.5) x 1.5 = 1.5 ine Az= 1.5in? 72 = 73 = 1+ = 1.5 in Area- A4= (5.5+1.5x (0.5+0.5) in2 = Tin

YA = 1+ (5.5+1.5) in 4.5 in Y = A, G + A2 Zz i Az Tz + A4 Yq Ait Azt Azt A 4 5x0.5+ 1.5X1.5+ 1.5*1.5+ 7x4.5 5 + 1.5 + 1.5+7 38,5 15 c 2.56 nam inch