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Question 47 (1 point) Calculate the pH of a solution that is 0.310 Min sodium formate...
Question 52 (1 point) For a reaction Keq - 1.2 x 10-6 at T = 298 K. What is AG for the reaction? -53.6 kJ/mol 53.6 kJ/mol 0-22.7 kJ/mol 33.8 kJ/mol 22.7 kJ/mol Question 47 (1 point) Calculate the pH of a solution that is 0.310 Min sodium formate (NaHCO2) and 0.190M in formic acid (HCO2H). The Kof formic acid is 1.77 x 10-4. 13.79 3.532 3.958 O 4.975 10.04
Question 56 (1 point) Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) 3 Cl2(g) + 2 Fe(s) → 6 (aq) + 2 Fe3+(aq) E° = +1.36 V Cl2(g) + 2 e 2 Cl(aq) Fe3+(aq) + 3 e → Fe(s) E° = -0.04 V O-1.32 V +4.16 V +1.40 V -1.40 V +1.32 V Question 55 (1 point) Calculate AGrxn at...
Calculate the pH of a solution that is 0.290 M in sodium formate (NaHCO2) and 0.210 M in formic acid (HCO2H). The Ka of formic acid is 1.77 ⋅ 10-4.
Calculate the pH of a solution that is 0.278 M in sodium formate (NaHCO2) and 0.091 M in formic acid (HCO2H). The Ka of formic acid is 1.77 x 10-4 ha OA 3.843 8.4.237 OC 13.90 OD.10.16 OE 4.954
Calculate the pH of a solution made by adding 48.0 g of sodium formate, NaHCOO, to 100. mL of 0.21 M formic acid, HCOOH. Hint what kind of solution is made? The Ka for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places.
Calculate the pH of a solution made by adding 34.0 g of sodium formate, NaHCOO, to 400. mL of 0.31 M formic acid, HCOOH. Hint what kind of solution is made? The Ka for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places.
Calculate the pH of a solution made by adding 35.0 g of sodium formate, NaHCOo, to 100 mL of 0.21 M formic acid, HCOOH. Hint what kind of solution is made? The K, for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places. Answer:
Calculate the pH of a solution made by adding 35.0 g of sodium formate, NaHCOO, to 100. mL of 0.21 M formic acid, HCOOH. Hint what kind of solution is made? The K, for HCOOH is 1.8 x 10-4 M. As usual, report pH to 2 decimal places. Answer:
Calculate the pH of a 0.23 M sodium formate solution (HCOONa). ^b for HCOO = 5.9 X 10-11 pH=D Zn(OH)2 is an amphoteric hydroxide. Write balanced ionic equations to show its reaction with (a) HCI 2 HCl(aq) + Zn(OH)2(5) ► (b) NaOH the product is Zn(OH)42-] NaOH(aq) + Zn(OH)2(5) ►
1. Calculate pH and % ionization of 0.25 M Naco (Ka (HCO2H) 1.8 x 10") 2- Calculate the pH of: a) 0.35 M HNO b) 0.15 M Sr(O)2 c) 0.08 M Ba(CIO4)2 3- Calculate the pH of 0.375 L buffer solution made of a 0.18 M Acetic acid HC2H:02(Ka 1.8x 10) and a 0.134 M Potassium acetate KC2Hs02 (do not use more than 3 digits beyond the decimal point) a) before adding anything b) after adding 0.010 mol Ba(OH)2 c)...