Question

6. What is the minimum radius in feet for a horizontal curve with a superelevation of 0.04? Use AASHTOs design value (0.12)

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Answer #1

Given,

Design speed,v=60mph=88ft/sec

e=0.04

f=0.12

Radius,R=?

Using relation given below

e+f=v²/(gR)

R=v²/((g)*(e+f))

R=(88²)/((32.1741)*(0.04+0.12))

R=1504.315583ft≈1510ft

Options B 1510ft is most appropriate.

Thankyou please Do Vote

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