We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
T 14. If 15.7 g of naphthalene, C10H8, is dissolved in 124.2 g of chloroform, CHCl3,...
If 64.0 g of naphthalene (C10H8, MW = 128) is dissolved in 144 g of benzene (C6H6, MW = 78), what is: a) the molality of the solution? b) the mole fraction of the solvent?
A 2.50 g sample of naphthalene, C10H8, was dissolved in 100 g of benzene. What is the freezing point of the solution? The freezing point of pure benzene is 5.45 degrees Celsius; Kf=5.07 degrees Celsius/m. The molar mass of C10H8 is 128.17 g/mol The answer is supposed to be 4.46 degrees Celsius. How did they get there?
A 3.314−g sample of a mixture of cyclohexane (C6H12) and naphthalene (C10H8) is dissolved in 45.40 g of benzene (C6H6). The freezing point of the solution is 2.00 ° C. Calculate the mass percent of the mixture.
Determine the freezing point of a solution that contains 65.4 g of naphthalene (C10H8) dissolved i 835 mL of benzene (density -0.877 g/mL). Pure benzene has a freezing point of 5.50°C and a freezing point depression constant of 4.90°C/m.
A solution contains naphthalene (C10H8) dissolved in hexane (C6H14) at a concentration of 11.17 % naphthalene by mass. Calculate the vapor pressure at 25 ∘C of hexane above the solution. The vapor pressure of pure hexane at 25 ∘C is 151 torr. Express the answer using three significant figures.
Chloroform boils at 61.3oC. What mass of naphthalene (C10H8 mw=128 amu) would be needed to raise the boiling point of 25.0 g of chloroform to 68.3oC if the boiling point elevation constant for chloroform is 3.63 oC/m B4 A) 6.2 g napthelene B) 19.3 g napthelene C) 0.635 g napthelene D) 2.09 g napthelene E) None of the above
How many grams of sulfur (S8) must be dissolved in 100.0 naphthalene (C10H8) to make a 0.12 m solution?
Find the boiling and freezing point of a solution prepared by dissolving 12.5g of naphthalene (C10H8) in 450g of chloroform. Melting and freezing points of pure chloroform are -36.5 celsius and 61.2 celsius.
A polymer of large molar mass is dissolved in the organic solvent chloroform (CHCl3) at 25 °C, and the resulting solution rises to a final height of 7.99 cm above the level of the pure solvent, as solvent molecules pass through a semipermeable membrane into the solution. If the solution contains 3.97 g polymer per liter, calculate the molar mass of the polymer. Take the density of the solution to be 1.48 g cm-3.
Your lab partner combined chloroform (CHCl3) and acetone (C3H60) to create a solution where the mole fraction of chloroform, Xchloroform, is 0.219. The densities of chloroform and acetone are 1.48 g/mL and 0.791 g/mL, respectively. Calculate the molarity of the solution. Number Calculate the molality of the solution. Number Imi ITI