Question

(5 points) The angle of elevation from a sailboat in a lake to the top of a vertical cliff is 45° The sailboat is 210 feet from the foot of the cliff. How high is the clit? Teet • Round your answer to the nearest foot.

Answer 1

The adjoining figure shows Situation given in question the D D 145 yo it means Sailboat Given : Angle of elevation of verticle Cliff which is Verticle at point ^' in figure = 45° + Cliff ALSO, The sailboat is 210 feet from the foot of the cliff, BC = 210 feet In Right angled triangle ABC 1 LB-90, LC-45° BC = 210 feet the sum of angles of a triangle hence LA = 180° ~ (909+ LB) 180° - (90 +45°) = 180-135º = 45° We know that is 180° 2 + LA LA

megns ALSO, The o ABC has two angles are equal Hence it is Isosceleces it the two sides A B & BC are equat hence AB, cohich is height of cliff is equal to feet. Height of Verticle cliff = 210 feet. And 210