Question

9.6.30 A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 160 yards from the center of the green. While standing on the marker and facing the green, the golfer turns 100° toward his ball. He then paces off 46 yards to his ball. See figure. How far is it to the center of the green? 160 yd 100° s 46 yd What is the distance? yd (Round to the nearest whole number)

I could really use help with these please

Answer 1

Answer 160gb here point are AIBIC 100 B AB=160-61 BC= 46-2 6' Ac=6=? LB = 46 using cosine law Cos B = a?+C? - 62 2ae 204 cos B = 9+62-5? b? - atc? - Zal cos b= 46 +1602 - 2x 46 x 160 cospoo 52 = 2116 + 25600 - 14720 ( -0.1736) - 27716 + 2 556.10 = 173.988 b = 302727 so b = 174 Hd so distance from center is 174 Yd Ans 0-6 C-8 B=97.9 using cosine rule (OSB = a²+ c² - 6² 2 ce 62 96 Cos 97.9 = 0 +82-62 36+64 286 X8 6² 100 - 96 (OS 97.9 6² = 100 - 96 (-0.1374 - 113-1946 b² = 113.1946 113.1946 b = 6 = 10:6392 b - 10.6 Ang

Freel 3). a = 5 b 2.B = 53 <C = 62 In a tringle sum of all angles = 180 ON a= 5 A 53 LA + 2B + Lc = IPO LA 180-4CB+C) = В Ipo - (53 +62) LA 65 so only only one solution for tringle so Dption B sing sine sule @ sinA b SIAB a Sina C sinc b = 5 sin 53 s sin 62 sin65 sin 65 be 4.40 (c = 4.87 Ang Ang

I solve all three

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