I know the answer is not C. Can you help me out please?!?
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I know the answer is not C. Can you help me out please?!?
18. If the...
Can someone help me with these? General Chemistry II - Worksheet 37 2. You are working...
Can someone help me with these?
General Chemistry II - Worksheet 37 2. You are working with a galvanic cell described by the overall reaction below. It is not under standard conditions. You add some ZnCl, to the anode compartment. Does the cell potential go up or down. 2V0." (aq) + 4H+ + Zn(s) -- 2V0 (aq) + 2H2O(0) + Zn°(aa) Answer Explain: 4. Calculate E at 310 K for the cell based on the reaction: Fe's(aq) + Cu (aq)...
with the information and tables provided, can you help me answer questions 2,3,4,and 5? thank you!...
with the information and tables provided, can you help me
answer questions 2,3,4,and 5? thank you!
DATA ANALYSIS - ONLINE SIMULATION DATA Record your collected data here. Black Red E (V) Cu Zn -1.10 Cu Sn -0.48 Cu Mg -2.71 Cu Ag 0.46 QUALITY OF DATA This section awards marks based on the quality of your Ell values. Quality of data Your standard cell potentials are in the expected order. EXPECTED DATA The expected data is given below. Use the...
Use the information given below to answer the questions about this standard electrochemical cell. ξo(V) Cu2+(aq)...
Use the information given below to answer the questions about this standard electrochemical cell. ξo(V) Cu2+(aq) + 2 e- → Cu (s) + 0.34 Zn2+(aq) + 2 e-→ Zn (s) - 0.76 Mark each of these statements as True or False. a.) The concentration of Cu2+ decreases as the reaction proceeds. b.) The solid metal cathode decreases in mass. c.) Negatively charged ions flow from the salt bridge to the anode. d.) The electrons will flow from the anode to...
the answer is 4.73, but i do not know how he got the answer. thank you!...
the answer is 4.73, but i do not know how he got the answer.
thank you!
(4) The Standard cell potential of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2H+ (aq) = Zn²+ (aq) + H₂lg). with PH2 = 1.0 am and [zn 2] = 0 , the cell potential 0.48M. what is pH in cathodic department?
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s)...
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s) Cu2+ (aq) + 2e + Cu(s) Zn2+ (aq) + 2e → Zn(s) E (V) -0.44 0.86 0.80 0.34 - 0.76 Using the table, calculate Eºcell for the following electrochemical cell under standard conditions voltmeter a) 1.24 V Fe. salt bridge Ag b) -1.24 V c) 2.04 V d) - 2.04 V Ag a b С
I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help...
I need help with questione 1-12 and discussion question 1 and
2. The previous pictures help determine the chart. Please Show Work
thank you so much
An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
please show work and how they got the answer 13. If [Cu2+] = 0.30 M for...
please show work and how they got the answer
13. If [Cu2+] = 0.30 M for the same cell described below, then what concentration of Fe2+ is needed to result in Ecell = 0.76 V? You will need to use the standard reduction potential table. Cu2+/ Cu → E = +0.34 V Fe2+/ Fe → E = -0.45 Cu?* (aq) + Fe(s) - Fe* (aq) + Cu(s) Eºcell = +0.78 V, Q = x/ 0.30, X = [Fe2+], Using Nernst,...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2:...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
please help fill out chart 1 by using the data belowed thank you! DATA:Cag] "Ay No₃...
please help fill out chart 1 by using the data belowed thank
you!
DATA:Cag] "Ay No₃ cell cell CUCNO3)27144-1.0m AgNO3 ! Agu = 10M Part I: Cell Potential of voltaic cells under standard conditions: Give the half Half cell reaction at Oxidation Combinations Reduction E the anode and Theoretical with [ion] takes place takes place cathode. Write in M here here (V) above the arrow if it is oxidation or reduction. -0.340 Ag - Cu Cucs) Agters oxi Anode: 0.3440.00...
Please help, thanks. Use the table below to answer the questions that follow. Half Reaction &
Please help, thanks. Use the table below to answer the questions that follow. Half Reaction E°(V) Ag+ + e- → Ag (s) +0.80 Cu2+ + 2e- → Cu (s) +0.34 Pb2+ + 2e- → Pb (s) -0.13 Ni2+ + 2e- → Ni (s) -0.28 (A) Calculate E°cell for a voltaic cell made with Ni, Ni2+and Ag, and Ag+. (B) Which substance is Oxidized? (be sure to include the state of the oxidized substance in your answer) Zn(s) + CuSO4(aq) -->...
Can someone help me with these?
General Chemistry II - Worksheet 37 2. You are working with a galvanic cell described by the overall reaction below. It is not under standard conditions. You add some ZnCl, to the anode compartment. Does the cell potential go up or down. 2V0." (aq) + 4H+ + Zn(s) -- 2V0 (aq) + 2H2O(0) + Zn°(aa) Answer Explain: 4. Calculate E at 310 K for the cell based on the reaction: Fe's(aq) + Cu (aq)...
with the information and tables provided, can you help me
answer questions 2,3,4,and 5? thank you!
DATA ANALYSIS - ONLINE SIMULATION DATA Record your collected data here. Black Red E (V) Cu Zn -1.10 Cu Sn -0.48 Cu Mg -2.71 Cu Ag 0.46 QUALITY OF DATA This section awards marks based on the quality of your Ell values. Quality of data Your standard cell potentials are in the expected order. EXPECTED DATA The expected data is given below. Use the...
the answer is 4.73, but i do not know how he got the answer.
thank you!
(4) The Standard cell potential of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2H+ (aq) = Zn²+ (aq) + H₂lg). with PH2 = 1.0 am and [zn 2] = 0 , the cell potential 0.48M. what is pH in cathodic department?
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s) Cu2+ (aq) + 2e + Cu(s) Zn2+ (aq) + 2e → Zn(s) E (V) -0.44 0.86 0.80 0.34 - 0.76 Using the table, calculate Eºcell for the following electrochemical cell under standard conditions voltmeter a) 1.24 V Fe. salt bridge Ag b) -1.24 V c) 2.04 V d) - 2.04 V Ag a b С
I need help with questione 1-12 and discussion question 1 and
2. The previous pictures help determine the chart. Please Show Work
thank you so much
An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
please show work and how they got the answer
13. If [Cu2+] = 0.30 M for the same cell described below, then what concentration of Fe2+ is needed to result in Ecell = 0.76 V? You will need to use the standard reduction potential table. Cu2+/ Cu → E = +0.34 V Fe2+/ Fe → E = -0.45 Cu?* (aq) + Fe(s) - Fe* (aq) + Cu(s) Eºcell = +0.78 V, Q = x/ 0.30, X = [Fe2+], Using Nernst,...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
please help fill out chart 1 by using the data belowed thank
you!
DATA:Cag] "Ay No₃ cell cell CUCNO3)27144-1.0m AgNO3 ! Agu = 10M Part I: Cell Potential of voltaic cells under standard conditions: Give the half Half cell reaction at Oxidation Combinations Reduction E the anode and Theoretical with [ion] takes place takes place cathode. Write in M here here (V) above the arrow if it is oxidation or reduction. -0.340 Ag - Cu Cucs) Agters oxi Anode: 0.3440.00...
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