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Please help, thanks. Use the table below to answer the questions that follow.             Half Reaction               &

Please help, thanks.

Use the table below to answer the questions that follow.

            Half Reaction                                                E°(V)   

            Ag+ + e-  → Ag (s)                                     +0.80

            Cu2+ + 2e-  → Cu (s)                               +0.34

            Pb2+ + 2e-  → Pb (s)                               -0.13

            Ni2+ + 2e-  → Ni (s)                                 -0.28

(A) Calculate E°cell for a voltaic cell made with Ni, Ni2+and Ag, and Ag+.

(B) Which substance is Oxidized? (be sure to include the state of the oxidized substance in your answer)

Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s)

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Answer #1

The cell reaction is Ni(s)∣Ni2+(aq) || Ag+(aq)∣Ag(s)

so, anode : Ni ====> Ni2+ + 2e-

cathode ; Ag+ + e- ===> Ag

Eocell = Ecathode - E anode = 0.80 - (-0.28) = 1.08V

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