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42 Day 21. Secs 6.1 and 6.2 Hypothesis Testing et 12 Dage 1 of 1 These data are a random sample of data from patients in the

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Answer #1

The hypothesis being tested is:

H0: p = 0.5

Ha: p > 0.5

p̂ = 70/124 = 0.56

The test statistic, z = (p̂ - p)/√p(1-p)/n

z = (0.56 - 0.5)/√0.5(1-0.5)/124

z = 1.44

The p-value is 0.0754.

Since the p-value (0.0754) is greater than the significance level (0.05), we fail to reject the null hypothesis.

Therefore, we cannot support the claim.

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