Question

5. DETAILS KATZPSEF1 23.P.041. ASK YOUR TEACHER Charges A, B, and are arrayed along the y axis, with GA = -3.80 nC, 98 - 3.00 nC, and ac = 5.40 nC (see figure below). The distance between charges A and B isyu = 1.00 m, and the distance between charges B and C is Y2 = 3.00 m. 9A Yi y2 4c (a) What is the net electrostatic force on charge A? magnitude N direction -Select- (b) What is the net electrostatic force on charge B? magnitude N direction -Select- (c) What is the net electrostatic force on charge C? magnitude N direction ---Select- Submit Answer

Answer 1

= -38n Given QA = -3.8n0 = -3,8*109c q B = 3nc = 3x10c 5.4nc = 5.4x109c Yozin la met elechostatic force on charge a QB = 300 FAC and FAR both will act Y 2 = 3m along y direction so, net force will be equal to siune (EA) net sum of FAC and PAB FACI FAB KORA OLB K QARC 4,2 9x10 x 38x109 x 8x109 + 9x109 x 3.8 810 x 5:4 t 012 (412 102.64109 114.148169 N +Obn 11.548109 It act along -ve y direction (along Ac) on B AA TFCT TBA B so both forces Net force as will be attracted by A and repelled by c. will same direchon ( +y areis) along BA (EB) net - EBA + FBC and FBC .act en 'BA abc

K LB. QA f 2 Kag.ec yo 94109 x 34109 x 3.8*10 9 + 9x109x3x10 " x 5.4 X109 (182 (392 9x3x3.8810 +9x345.48109 3x3 (FB) net 118.88109 N ty anis along BA FEA 11 Sounc qc sum of x5:48109 © Net force on charge c. "QA = -3.800 AA will attract ac and a will qB = 300 repel az. so Forces FCA and Feiß will act opposite to each other wet FEB force acting on a will be algebric Fers and FCA SD FEA = KQAR 9x109x3.8x169 1912 = 11.548109 (along -y axis) FEBE KqAB 9x109 x 5,48109 x 34109 212 (3) 2 16.2 X100 (along ty quis) (Fc) net FB FCA 91.54) X109 El no 9.66 x 169 along eve y anis بولا , با (16.2