Answer-
According to the given question-
Here we have an enzyme-catalyzed, reaction observed in presence as well as the absence of inhibitor, and in the Lineweaver Burk plot, we have observed that-
1 Km = 10 ,
Km = 0.1
1 Km = 3.5
Km = 0.2857
Km Km = 0. 1 0.2857
1 = 0.35
= 1 0.35 = 2.857
= 1 + [I] KI
2.857 = 1 + (0.002) KI
2.857 KI = KI + 0.002
2.857 KI - KI = 0.002
1.857 KI = 0.002
KI = 0.001077 mM
KI = 1077nM
Thus the correct answer is (E) KI = 1077nM
An enzyme catalyzed reaction was performed in the presence and in the absence of an inhibitor....
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