An enzyme catalyzed reaction was performed in the presence and in the absence of an inhibitor....

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An enzyme catalyzed reaction was performed in the presence and in the absence of an inhibitor. The Lineweaver Burk plot showe

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Answer 1

Answer #1

Answer: d. 1nM

Calculations:

The Y-axis intercept in Lineweaver-Burk plot is equal to 1/V_max

Let the maximum reaction velocity in the presence and absence of the noncompetitive inhibitor be V_max' and Vmax

1/V_max' = 15

and 1/V_max = 5

In noncompetitive inhibition, the Y-intercept changes from 1/V_max to 1/V_max'

and 1/V_max' = a x 1/V_max (where a = 1 + [I]/K_I )

Thus, 15 = a x 5

or a = 15/5 = 3

K_I = 0.5nM

Now since a = 1 + [I]/K_I

3 = 1 + [I]/0.5

or [I] = 1 nM

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