Question

Enzyme Kinetics Problem The initial rate for an enzyme-catalyzed reaction has been determined at a number of substrate concen
0 0
Add a comment Improve this question Transcribed image text
Answer #1
S V 1/S 1/V
5 22 0.2 0.045455
10 39 0.1 0.025641
20 65 0.05 0.015385

70 Vmax 60 Vmax 65 50 V Km 8 umol 1/2 vmax km 40 30 20 10 Km 0 5 10 15 20 25 un C

LB plot 0.05 1/vmax= 0.005 Vmax = 200 0.045 0.04 0.035 166s slope km/vmax. 0.025 0.02 slope 0.035-0.025 /0.15-0.1 -0.01/0.05

Kcat = Vmax / Et

        = 200 / 1

Kcat = 200

Add a comment
Know the answer?
Add Answer to:
Enzyme Kinetics Problem The initial rate for an enzyme-catalyzed reaction has been determined at a number...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 8. The initial rate for an enzyme-catalyzed reaction has been deter mined at a number of...

    8. The initial rate for an enzyme-catalyzed reaction has been deter mined at a number of substrate concentrations. Data are as follows: (Sl (pmol/L) (pmol/L) min) 65 102 120 135 200 (a) Estimate Vmax and Ky from a direct graph of y versus (SI (these data are plotted in Figure 11.246). Do you find difficulties in get- ting clear answers? (b) Now use a Lineweaver-Burk plot to analyze the same data. Does this work better? 8. The initial rate for...

  • 4. The following data were obtained from an enzyme kinetics experiment. Graph the data using a...

    4. The following data were obtained from an enzyme kinetics experiment. Graph the data using a Lineweaver-Burk plot and determine, by inspection of the graph, the values for Km and Vmax. ISI (M) V (nmol/min) 0.20 0.26 0.33 1.00 1.43 1.67 2.08 3.33 5. You measured the kinetics of an enzyme activity as a function of substrate concentration (see Table). The enzyme concentration was maintained constant at a level of 1 M. [S] AM Vopmol/min 2.9 3.8 4.4 Plot the...

  • CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. T...

    CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. The rate of the reaction has been determined with and without an inhibitor. A total concentration of enzyme of 20 uM was used in the experiment. SHOW WORK AND UNITS!!! Without Inhibitor With Inhibitor [substrate] (mM)Rate of formation of te of formation of product product (mM/min) mM/min) 6.67 5.25 0.49 7.04 38.91 1.0 2.2 6.9 41.8 44.0 1.5 3.5 1 a) On the same graph, plot the data...

  • The kinetics of enzyme catalyzed reactions can be described the Michaelis-Menten equation and the Eadie-Hofstee equatio...

    The kinetics of enzyme catalyzed reactions can be described the Michaelis-Menten equation and the Eadie-Hofstee equation as shown below: V0 = (-Km) V0 / [S] + Vmax a). Please derive the Eadie-Hofstee equation starting from the Michaelis-Menten equation. b). The Vmax and Km of the enzyme catalyzed reaction can be derived from a plot of V0 versus V0/[S]. Please draw one of these plots and explain how do you use it to derive Vmax and Km. c). Please draw a...

  • 9. The following data were obtained from an enzyme kinetics experiment. Graph the data using a...

    9. The following data were obtained from an enzyme kinetics experiment. Graph the data using a Lineweaver-Burk plot and determine the values for Km and Vmax. [S] (UM) V(nmol/min) 0.20 0.26 1.43 1.67 2.08 3.33 0.33 1.00

  • 112 marks] 3. The relationship between initial velocity (V.) and substrate concentration of most of the...

    112 marks] 3. The relationship between initial velocity (V.) and substrate concentration of most of the enzyme- catalized reactions are explained by Michaelis-Menten equation. IMPORTANT: Show the calculations and indicate the units for all your answers. a. For an enzyme which follows the Michaelis-Menten enzyme kinetics, Km is 50 mmol L. Calculate the substrate concentration required to obtain the initial velocity (V.) equivalent to 90% of the maximum velocity (Vmax). b. The Vmax of the above reaction is 250 mmol...

  • 7. a) In an enzyme catalyzed reaction which follows the Michaelis-Menten kinetics. The substrate ...

    7. a) In an enzyme catalyzed reaction which follows the Michaelis-Menten kinetics. The substrate concentration (Km, Michaelis constant) needed to reach 50% of the maximum reaction velocity (Vmax) is 20 μΜ. What substrate concentration is required to obtain at least 75% of the maximum reaction velocity? Show the work to get full points. (5 points) b) You want to load 10 μg of protein in 15 μL into one of the 10% polyacrylamide gel well. The protein needs to be...

  • The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed react...

    The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...

  • The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the...

    The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the concentration of the substrate of the reaction ([S]). In Damon's Michaelis-Menten experiment, the highest concentration of substrate used was 500 UM. What do you think will happen to the reaction velocity if higher concentrations of substrate were used? Select one: a. Vo will reach a plateau at higher (S) values O b. Vo will increase exponentially as (S) is increased O c. Vo will...

  • An enzyme catalyzed reaction was performed in the presence and in the absence of an inhibitor....

    An enzyme catalyzed reaction was performed in the presence and in the absence of an inhibitor. The Lineweaver Burk plot showed competitive kinetics with x-intercepts of -10mm -1 and -3.5mm -1 in the presence and absence of the inhibitor respectively. If the inhibitor concentration used was 2micro molar (UM), calculate KI for the inhibitor enzyme binding? a. none of the above b. 0.135nM c. 0.054nM d. 0.225nM e. 1077 nM

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT