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Question 10. Bacterial density in a counting chamber A scientist needs to calculate the density of a bacterial culture in ord

I need the answer to question D, thank you.

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Answer #1

Total volume = 0.000002 × 5 = 10^-5 uL

Total # cells = 264 + 287 + 240 + 267 + 251 = 1309

10^-5 uL = 1309 cells

1 uL = 1309 / 10^-5 = 1309 × 10^5 = 1.309 × 10^8 cells per uL

1 uL = 10^-3 mL

10^-3 mL = 1.309 × 10^8 cells

1 mL = 1.309 × 10^8 / 10^-3 = 1.309 × 10^11 cells per mL

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