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RE Let H be the hemisphere x2 + y2 + 2 = 35, z 2 0, and suppose f is a continuous function with f(5, 1, 3) = 14, A5, -1, 3) -
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Solutions Let & &Z=35 H be the hemisphere xtyht ble know that shty + 2 = 83 compare 356 Z 20 2 with we get 2 equation :35 Th4 AS = TOT 4 to SS fexag, 2) ds Å f (x4,91 Z;) AS * Now Divide it into four patches: Therefore Area of each patch is for Gire

SSfex,11z)ds - 70 70 (f (1,3,774) +6C8218218.) +143,43123) +(2414424) = FOUC 144 14+15+16) q 7011(59) 4 a T0TX 14.75 =1032.5

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