Homework Answers
sample mean, xbar = 253
sample standard deviation, s = 11.4
sample size, n = 101
degrees of freedom, df = n - 1 = 100
Given CI level is 99%, hence α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005, tc = t(α/2, df) = 2.626
ME = tc * s/sqrt(n)
ME = 2.626 * 11.4/sqrt(101)
ME = 2.979
CI = (xbar - tc * s/sqrt(n) , xbar + tc * s/sqrt(n))
CI = (253 - 2.626 * 11.4/sqrt(101) , 253 + 2.626 *
11.4/sqrt(101))
CI = (250.02 , 255.98)
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