Question

1

Water is poured into a container that has a leak. The mass m of the water is given as a function of time t by m = 5.50.8. 2.5t + 22, with t2 0 m in grams, and in seconds. (a) At what time is the water mass greatest, and (b) what is that greatest mass? What is the rate of mass change at (c) t = 2.0 s and (d) t = 5.27 (a) Number: Unit: 5 (b) Number Unit 9 (c) Number: Unit: (d) Number: Unit:

Answer 1

ΑΣ 0:8 m = 5.5t zist +22 dm/dt =0 For greatest water-man : 3,5x0,8 215 D-> 4,4 0.2 t 215 0.2 t = 16.8875 B) from egh (U ma sis (16,887)018 – 12.5x161887) +22 greatest man m = 321554 g 215 0.2 Rate of man- change dm = 414 dt to12 at t=2$. am 4.4 - 215 012 at t=25 am = 1,330 g/$ at t=28 (2)002 at t=5.2$, dm at t=5.25 4,4 215 (5,2)º2 0.664 g/§ dim at t=5,2$