Find C(A) 1 -3 4 -1 9 -26 -6 -1 -10 -3 9 -6 -6 -3 A = 3 -94 9 0 O a. 3 -1 6 - 1 C(A) -6 9 9 O b. -4 -9 2 6 C(A) 3 6 -4 0 8 C(A) = ON fono 0 O d. 4 9 -2 -6 C(A) = -10 -3 -3 -6 3 4 0 O C(A) = O o 0 Of. 1 4 *** 6 C(A) = -2 -3...
Find N(A) A= 1 -3 4 - 1 9 -2 6 -6 -1 -10 -39 -6 -6 -3 3 -94 9 0 oa. 1 -2 -3 3 - 3 6 9 N(A) = 4 -6 -1 -6 -1 -10 -6 9 9 0 3 0 N(A) 1 0 2 0 N(A) = 2 1 0 -2 0 d. 3 -10 0 N(A) 2 0 0 N(A) -2 6 -3 4 N(A) = -1 -6 -1 -10 9
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Find N(A) 1 -3 4 -1 9 A = -2 6 -6 -1 -10 -3 9 -6 -6 -3 mo 3 -94 9 a. 1 -2 6 -3 N(A) = -6 -1 -10 Ob. 10 0 N(A) 3 2 0 3 -5 0 N(A) = 0 0 0 2 O d. 2 ܩ ܘ ܚ N(A) 1 0 0 0 2 e. 2. 3 3 -3 6 9 -9 N(A) = -6 -6...
linear algebra 2 part mcq
part a
part b
H Let be the set of third degree polynomials H = {ax + ax? + ax' | AEC) P3 why or why not? H Is a subspace of Select all correct answer choices (there may be more than one). a. H P3 is a subspace of because it can be written as the span of a subset of b. H is a subspace of because it contains only second degree polynomials...
Find N(A) A = 1 -3 4 -1 9 -2 6 -6 -1 -10 -3 9 -6 -6 -3 3 -9 4 9 0
linear algebra
part a
part b
Find N(A) A = 1 -3 4 -1 9 -2 6 -6 -1 -10 -39 -6 -6 -3 3-94 9 0 a. 6 N(A) = 4 -1 ୨ 10 E. N(A) = 0 3 2 ) 0 0 C T ୨ NA - -6 -1 -10. -] ୨ =5 - -] ୨ ) d, N(A) = 3 0 0 2 0 5 1 1 0 0 0 NA - 1 1 0 0 -2...
Find C(A) A = 1 -3 4 -1 9 -2 6 -6 -1 -10 9 -6 -6 -3 3 -9 4 90 ليا
Find r(A) and n(A) A = 1 -34 -1 9 -2 6 -6 -1 -10 -3 9 -6 -6 -3 3 -9 4 9 0 O a.r(A) = 1 n(A) = 4 b.r(A) = 4 n(A) = 1 cr(A) = 5 n(A) = 0 d.r(A) = 2 n(A) = 3 Oer(A) = 0 n(A) = 5 Of.r(A) = 3 n(A) = 2
Find
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b.
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Find C(A) 1 A = - 3 4 -1 9 -2 6 -6 -1 -10 -3 9 -6 -6 -3 3 -9 4 9 0 a. -1 -1 C(A) = b. O NO C(A) = -4 2 10 C(A) = -3 -4 d. -2 C(A) = -6 -6 -3 3 e. 4 9 1 -2 -6 -10 C(A) -3 -3 3 4 0 Of. 0 C(A) = O O 0 O O O...
Find (A) and n(A) A = 1 - 3 4 -1 9 -2 6 -6 -1 -10 - 39 -6 -6 -3 3 -9 4 9 0