5) (Read the directions carefully!) For this problem, you will use rectangles to approximate the area...
full steps and how to solve please 1. Let y-x'. a) Using 4 rectangles of equal width (Ar-2 )and the right endpoint of the subinterval for the height of the rectangle, estimate the area under the curve on the interval [0,8. Then sketch a graph of the function over the interval along with the rectangles. b) Using 4 rectangles of equal width (Ax 2 and the left endpoint of the subinterval for the height of the rectangle, estimate the area...
under the Curve 2. Let y e2". a) Using 4 rectangles of equal width (Δ 1)and the rightendpoint of the subinterval for the height of the rectangle, estimate the area under the curve on the interval [0,4]. Then sketch a graph of the function over the interval along with the rectangles. b) Using 4 rectangles of equal width (Ax 1)and the left endpoint of the subinterval for the height of the rectangle, estimate the area under the curve on the...
Approximate the area under the following curve and above the x-axis on the given interval, using rectangles whose height is the value of the function at the left side of the rectangle (a) Use two rectangles. (b) Use four rectangles. (c) Use a graphing calculator (or other technology) and 40 rectangles. f(x)-2-x-1,1 (a) The approximated area when using two rectangles is square units (Type an integer or decimal rounded to two decimal places as needed.) (b) The approximated area when...
Use the rectangles to approximate the area of the region. f(x) = -x + 11 [1, 11] y 10 8 6 2 2 4 6 8 10 10 Х Give the exact area obtained using a definite integral. 10 x Need Help? Read it Watch It Talk to a Tutor Use the rectangles to approximate the area of the region. (Round your answer to three decimal places.) f(x) = 25 – x2, (-5,5) y 23 20 15 10 -6 2...
Approximate the area under the graph of f()=0.037 -2892 +98 over the interval [5.9] by dividing the interval into 4 subintervals. Use the left endpoint of each subinterval The area under the graph of fix) = 0.037 -28972 +98 over the interval [5.9 is approximately I (Simplify your answer. Type an integer or a decimal Approximate the area under the graph of f(x)=0.03** -2.89x2.98 over the interval 15.9| by dividing the interval into 4 subintervals. Use the left endpoint of...
Approximate the area of the region bounded by the graph of f(t) f(t) cos(t/2-7t / 8) (t/2-7T/8) and the cos t-axis on [7T/8,15/ 8] with n 4 subintervals. Use the midpoint of each subinterval to determine the height of each rectangle (see figure) 0.5 27 2 The approximate area of the region is (Round to two decimal places as needed.) N| a. Approximate the area of the region bounded by the graph of f(t) f(t) cos(t/2-7t / 8) (t/2-7T/8) and...
Approximate the area under the graph of F(x)=0.7x3 +7x2-0.7x-7over the interval [-9,-4) height of the rectangles using 5 subintervals. Use the left endpoints to fird te The area is approximately (Type an integer or a decimal)
Approximate the area under the graph of f(x) over the specified interval by dividing the interval in number of subintervals and using the left endpoint of each subinterval. 20) f(x) = x2+2; interval [0,5); 5 subintervals A) 66 B) 40 C) 65 201 D) 32 Printed by Ana Dallallallalia mail done e
+1 4 In each of the following graphs there are six rectangles. The area under the graph of f(x) between the vertical lines x=0, x=2 and the x-axis is also shaded RRRR 051 152 RRRRRR • Approximate the area under the curve by considering a lower bound and an upper bound. Why do you think that more rectangles are being used? • Complete the following tables to organize the information. You can create a table with your GDC to calculate...
(1 point) In this problem you will calculate the area between f(x) = x2 and the x-axis over the interval [3,12] using a limit of right-endpoint Riemann sums: Area = lim ( f(xxAx bir (3 forwar). Express the following quantities in terms of n, the number of rectangles in the Riemann sum, and k, the index for the rectangles in the Riemann sum. a. We start by subdividing [3, 12) into n equal width subintervals [x0, x1], [x1, x2),..., [Xn-1,...