Question

3.) For this problem you need to generate data so open the probability simulator on the TI calculator and set your seed (Use last 4 digits of your GCID). Select the Roll Dice simulator and set the number of trials to 16, and the number of Sides to 12. Execute Roll and save Data to a list. PROB SIM APP Call the corresponding random variable X. Settings Trial Set: 16 Dice: 1 2 3 Sides: 6 8 10 12 20 Graph: Freg Prob Store Table: No All 50 Clear Table: Yes No Update After: 1 20 50 End SEED NUMBER: 3932 Data: ESC ADVI OK 7 10 7 3 11 11 8 8 2 7 8 2 7 10 6 5 Calculate the following statistics from your data: a.) the sample mean, X = 7 b.) the sample standard deviation, Sy = 4.5460 c.) the median: 7 d.) the Inter Quartile Range, IQR= 5.25 e.) Is the data distribution skewed left? right? or is it symmetric? Answer:

Answer 1

given as, 7 1 3) The data is given 10 7, 3, 11, 11, 8, 8, 2, 7, 8, 2, 7, 10, 6,5 Arranging it in ascender order, we get 2, 2, 3, 5, 6, 7, 7, 7, 7, 8, 8, 8, 10, 10, 11, 11, a) The sample mean will be +11 X 4 x 2+ 2+ 3+ 16 - given as, - n 7 So the 112 16. sample mean is 7. sample standard deviation will be, ${xi – 7,)? b) The st n-1 (2-7)+(2-7) + (11-7² 2.8751 124 JS is 2.8751. So the standard deviation

c) The median size of (N+1) will be, th item M= size q (16+17th item -size of (8.5th item th = 8th itemt item 2 - 7+7 > 7 2 So the median i 7. d) The interquartile range is , IQR = Q3 - di I (N+1th item item QI + 16 +ith = (4.25th i 4 Q yth item + 0.25 (sthitem -4th item 5 +0.25(6-5) 5.25. so IQ, 5.25 th th 12.75 item Q3 ? (N+1) (16+15th 3 item 3 4. 4. 12th item + 0.75| 13th item - 12th item) 8+ 0.75 | 10-8 gos 2. Q3 =ges 9.5-5.25 :.1QR = to the interquartile range 4.25 is 4.25.

it is e) The mean is 7 and median is also 7. The mode will also the be equal to 7 because most frequent observations: Since mode= median, the distribution i symmetrical mean =

As you have posted more than 1 question, I am answering the first one. If you also require the unanswered question, please re-post it separately.