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The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VA, VB, and Vc). The res

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Answer #1

We find the total current in the circuit.Using current division rule the current through R2 is calculated.We apply the power formula to calculate the power dissipated by R2.Vc Riž I VB VA Ra TH R3 RallR₃ 622116-2 = 666 6+6 Currest I = VB+Vc-VB Rit (R2/1R3) = 15 + 20-25 2 + 3 = 2A G Ira 6 1 A - IX

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