Question

Two Loop RC Circuit 1 3 Standard Multig -O RE A circuit is constructed with four resistors, one capacitor, one battery and a switch as shown. The values for the resistors are: R = R2 = 630, R3 = 92 Q and Ry = 750. The capacitance is C = 42 pF and the battery voltage is V 24 V Interact 3r2c v R; Standard Two Standard Two L 1) The switch has been open for a long time when at time t = 0, the switch is closed. What is 1,(0), the magnitude of the current through the resistor R, just after the switch is closed? 0.1739 Submit You currently have 2 submissions for this question. Only 10 submission are allowed. You can make 8 more submissions for this question Standard RC Ci -O Standar Capa -- 2) What is 1,(-), the magnitude of the current that flows through the resistor R, a very long time after the switch has been closed? 10.08191 A Submit You currently have 2 submissions for this question. Only 10 submission are allowed. You can make 8 more submissions for this question 3) What is Q), the charge on the capacitor after the switch has been closed for a very long time? 316.50024 UC Submit You currently have 4 submissions for this question. Only 10 submission are allowed. You can make 6 more submissions for this question 4) Consider the circuit above, with Rs = 650 in series with the capacitor Once again, the switch has been open for a long time when at time to 0, the switch is closed. What is 1,(0), the magnitude of the current through the resistor R. just after the switch is closed? Ri с

Answer 1

Ri R M Ra 0 at t=0 tiles AM Ru tile, initially capacitor acts chort Circuit . The circuit is PR shown Tu R3 Since the capacitor is short- Circuited the total current pass through it. Therefore in Ry no current R₂ 8 Rz. V= i. (RitRu) 1,- Pitru 24 63+75 n = 0.1739. Amp

for means, t=0 long time capacitor acts at t=0 as open Circuit Ri R2 v=i (Rit R₂ + R₂ + R4) R3 I Ru R,+ R₂ + R₂ + Ry 24 63+63 + 92+75 24 293 0.08191 Amp.

③ The circuit after long time is The potential differenca 101 AB IS Ry Scapacitar a in parallel to (R₂+2) potential of capacitor VAYB = i (R+R) - VAB = {(B&B) VAB = 0.08191 ( 63 +92) VAB = 12.69605 CVAB Q- (42x106) (12.69605) -6 Q- 533.234 / X10 533. 2344 UC

Now, RS in series with capacitor, But at t=0 the capacitor acts as short corcuit ciruit R looks like I Rg Ru series. Here R21 R are in equivalent of R28 R₂ is (R+R₂) = R' is The cirwit RI } p. (RtR2) RS R = 1552

are Now, R & Ro parallel equivalent of pl 8 Rg be Ri Llet) R" = RX R5 155 X 65 45.795 155+65 The circuit Pl+ Rs Ri M Ru Ry V i (RitR" + Ru 24 = 1,- 63+75 +45.795 Ryt RutR" i, 24 -0.1306 Amp 183.7954 ii 0-1306 Amp