Question

equation for the quantity, Q, Hydrocodone bitartrate is used as a coogh supp verant. After the dring is fully absorbed, the quantity of drug in the baly decreases at a rate proportional to the amount left in the body, The half-life of hydrocodone birate in the body is 3.8 hours & the dose is 10mg. a) write a differential of hydrocodone bitartrate in the body, lehetne esclares at time t, in hours Since the drug was a fully absorved. Solve the differential equation. b) using your differential equation you. the previous question, use the half-life to find the constant of proportionality & then how much of the 10 mg dose is still in the body after 12 hours? found in

Answer 1

core rate There some moterice which disintegrate it a proportional to the amount present for example, Hydrocodone bitartrate be the material /dung efter oborking fully, the quantity(a) of drug in the body decreases al reste proportional to the amount left in the body de dQ at oc da dt -la where d is constant . decey are sign indicate that quantity of drug is decreasing given So the required differential question is where & is quantity present at any time t. од (2) dia dt -dQ (6 Since helf life of hydrocodone betartrate t - 3-8 hre d In 2 0.693 3.8 a .18 ولمل -it amount . The solution of above differential ep" & lo e where & is initial do tomg (guien) Now the quanlity of drug left after t=12 hes is quien OS 18812 Q = lo e

Q- -2-16 10 e Q = toxo12 Q 1.2 mg So the quantity of quantity of hydrocodone bitartrate lef cofter cits absorption 1-2 mg left after 12 here eis