Question

A 5000 lb tank gun tube is modeled below connected to the turret by a pin connection that allows rotation about the pin axis. When 0 = 53.13 degrees, the angular velocity of the gun tube is 10 rad/sec as shown. The turret is rotating about the vertical axis at a constant rate of N = 2 rad/sec. Determine the angular acceleration of the gun tube, Ö, and the couple reaction exerted by the gun tube on the pin at point A. Frome F B 9 15 ft X FRANE I

Answer 1

Date Page sol: .X img х l = 15 ft = 4.572m O=53:13 Wp = I2 = 2 rad/sec W = 5000 lb mg = 5000 lb -445 X 500 N 10 rad/sec Imo Gyroscopic couple G-IWP 30-02 But c= mg cos(90-0) x l 2- 2 mg { cos(90-0) = I w6p I moment of a Inertia 41458500 * 41572 cos(90–53.13) 2 = I xlox2 » I = 203.453 kg-m²

Pago Now couple Reaction at point. A C = IWWp E 203.453 X10 X2 C - 4069.06 N-m G = 4069.06 Nem C 30011846 lb-ft nswer Angular cech of the gun tube 16 ) C - Torque or couple IX angular (Xove) aceh 4069,06 = I a xor å = 4069.06 I 4069.06 203.453 - 20 ad/seet ö