1. (10 p) Determine the final temperature of the liquid when you mix: m = 1.00...
Determine the final temperature of the liquid when you
mix:
m1 = 1.00 kg water at t1 = 10.0 °C
and
m2 = 2.00 kg water at t2 = 40.0 °C.
Assume that no heat is lost to the environment.
A numerical value is required for credit.
SHOW YOUR WORK.
Formulas: Heat: Q = mcAT Q1 + Q2 + ...=0 Calorimetry:
Determine the final temperature of the liquid
when you mix:
m1 = 1.00 kg water at
t1 = 10.0 °C and m2
= 2.00 kg water at t2 = 40.0
°C.
Assume that no heat is lost to the environment.
FORMULAS:
Q1 + Q2 + .... + = 0
q= mcЛТ
Determine the final temperature of the liquid when you mix: m1 = 1.00 kg water at t1 = 10.0 °C and m2 = 2.00 kg water at t2 = 40.0 °C. Assume that no heat is lost to the environment. A numerical value is required for credit. SHOW YOUR WORK.
Determine the final temperature of the liquid
when you mix:
m1 = 1.00 kg water at
t1 = 10.0 °C
and
m2 = 2.00 kg water at
t2 = 40.0 °C.
Assume that no heat is lost to the environment.
Q = mcT
Lab-10: Calorimetry: Specific Heat of a Metal DATA SHEETS: Reference: Chapter Notes-10 and Lab Manual (Pages 64 to 70) Use the following You Tubes to get more information https://youtu.be/8gHFOL2990U https://youtu.be/HlvilF6MI9c Calculate the Specific Heat and identify the Metal Observation Mass Mass of Metal (ml): 87.87 g Mass of polystyrene cup (m2): 2.32 g Mass of cup with water (m3): 72.82 g Mass of water in the cup (m3-m2): 70.5 g Temperature Initial temp. of Metal (the boiling water temperature (t1):...
please answer all questions
Temperature Change and Heat Capacity - Calorimetry- Two substances The quantitative relationship between heat transfer and temperature change is Q = mcAT, where Q is heat transfer, m is the mass of the substance, and AT is the change in temperature. The symbol c stands for specific heat and depends on the material and phase. The specific heat c is the amount of heat necessary to change the temperature of 1.00 kg of mass by 1.00°C....
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