a)
b)
expected frequency,E |
52.78 |
56.84 |
52.78 |
97.44 |
81.20 |
64.96 |
observed frequencey, O | expected proportion | expected frequency,E | (O-E) | (O-E)²/E | |
63 | 0.130 | 52.78 | 10.22 | 1.979 | |
65 | 0.140 | 56.84 | 8.16 | 1.171 | |
52 | 0.130 | 52.78 | -0.78 | 0.012 | |
61 | 0.240 | 97.44 | -36.44 | 13.628 | |
99 | 0.200 | 81.20 | 17.80 | 3.902 | |
66 | 0.160 | 64.960 | 1.04 | 0.017 |
chi square test statistic,X² = Σ(O-E)²/E =
20.708
Degree of freedom=k-1= 6 -
1 = 5
P value = 0.001 [ excel function:
=chisq.dist.rt(test-stat,df) ]
Please let me know in case of any doubt.
Thanks in advance!
Please upvote!
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