Question

The 500-lb concentrated load is perpendicular to the x-z plane and parallel with the y-axis. The Point A is located at the base of the support structure on the outside face of the hollow circular tube shown in Section X-X.

5 ft 500 lb 6.0 in 5.5 in Section X-X 25 ft Х N AM

a. Compute all stress resultants at the base of hollow circular tube and compute the stresses associated with each stress resultant at Point A.

b. Use Mohr’s Circle to find principal stresses and the maximum shear stress at Point A. [You do not need to determine angles or sketch stress elements.]

Answer 1

As per Suestion : 500 lb - 1 za 15:53 6" 25' Zk Free bi body Diagram. 500= ? (500x 5) = Mr (500x5 500 500 A 500 lb force (ازی give rise to force P and and a moment Ma in Py - Py force will Cause bending of which is responsible for tube I quis, about of the tensile stresses at My I

11 M: 500 x 25 x12 150,000 Jbioch c 3" ysl Is IC64-5-59) 18.7 inch 4 64 15x 104 x 3 2-4610" blinch 18.7 Py force is also it wil be O responsible for Stiear Stress, but at A, as "Shear stresses Р sections are at entreames of ii) Mut win. Mu is responsible shear stress for forsional moment, which produce T= 7 T = Mn 500x 5x 12 = 30,00o Ibinch 6.3" J= A (6" - 5.5") = 37.4 inch" 32 T = 30xlo3x3 37.4 2.4x102 Joprosent a) ay T Z A qe PO

Tman (6, 7) х oa C 업 Co,-2) 2 :> Principal Stresses Centre & radius Centre = c5 caso Radius=r= Jo²+ 4T² 0/= I Jor40 2.4x104 +2.4x13) 12 x 104+ 1.2238 x 10" 0% - 2.4238x109 blinch? and -238 oblinen ii) Man Shear Shress radius Jo ²+47 = 1.2238x109 lb/inch? 2 a 2

Hope everything is clear.

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