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The cantilever beam shown in the figure is subjected to a concentrated load at point B. The stresses acting at point Hon the
C 40 mm (Note: The load P applied at Bacts in the x-y plane.) Enter the following section properties needed to calculate the
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Answer #1

19 by=15 - 150 mm hty = 137 twe 7 mm 1cau 40 A 16=0.3m q=1.75m 0=63 Resolving we get 49 KN in ne sy direction P= ugKN ch 6=0to inertia about z auis Heure Total M2 = 76.61 kNm 2 Shear force ath S = 43.65 KM Normal Tensile force moment 150X133 Iz 22.3.94 N/mm2 Tensile in Neituretor Total Nornay stress o=G+02 24689+3.94 on = 37.94 N/anime tutan Hence No. B-M about any othenI= 15 N/mm2 oz = -52.97 N/mm2 Zwax (-34.9492 +628-3072 Twox 34N/mm2

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