Sample size , n = 38
Probability of an event of interest, p = 0.01
P ( X = 0) = C (38,0) * 0.01^0 * ( 1 - 0.01)^38=
0.6826
P ( X = 1) = C (38,1) * 0.01^1 * ( 1 - 0.01)^37=
0.2620
P ( X = 2) = C (38,2) * 0.01^2 * ( 1 - 0.01)^36=
0.0490
P(accepeted) = P(X≤2) = P(X=0) + P(X=1) + P(X=2)= 0.9935
answer is order: 99.35%, 0.65%, almost all of the hipment will be accepted
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