Using Lagrange's interpolation formula find y(0.25) from the following table: x0.4 0.6 0.81 y 0.48 0.12...
Using Lagrange's interpolation formula find y(0.25) from the following table: x0.4 0.6 0.81 y 0.48 0.12 3.2 Write 3-decimal plates
Using Lagrange's interpolation formula find y(0.25) from the following table: x0.4 0.6 0.81 y 0.48 0.12 3.2 Write 3-decimal plates
Using Lagrange's interpolation formula find y(0.25) from the following table: x0.2 0.4 0.6 0.8 y 0.12 0.48 0.12 Write 3-decimal plates
Using Lagrange's interpolation formula find y(0.25) from the following table: x 0.4 0.6 0.8 1 y 0.48 0.12 3.2 Write 3-decimal plates 1 А" B I &?
Using Lagrange's interpolation formula find y(0.25) from the following table: x 0.2 0.4 0.6 0.8 y0.12 0.48 0.12 Write 3-decimal plates
Find Lox) using Lagrange interpolation formula from the following table
Problem 3: Interpolation, least squares, and finite difference Consider the following data table: 2 0 0.2 0.4 0.6 f(x) = 2 2.018 2.104 2.306 3 The quadratic Lagrange interpolator L2,0() used to quadratically interpolate between data points #1 = 0.12 = 0.2, and as = 0.4 is (Chop after 2 decimal places) None of the above -5.00x^2+7.50x+2.00 5.00x^2-1.00 12.50x^2-7.50x+1.00 25.05x^2-10.25%
Find the breakeven (Ai*) for the following projects (Incremental cash flow), Using interpolation. Note: Do not write the percentage sign (%) in the blank. Just write a number with two digits after decimal point like 18.32. А B -10.000 -60,000 First cost $ Annual operationg cost, $ Salvage value, $ -78,000 -65,000 6.000 11,000 Life year 3 6
Consider the following data table: 0 2i = 0.2 0.4 f(xi) = 2 2.018 2.104 2.306 0.6 0.2 and 23=0.4 is The linear Lagrange interpolator L1,1 (2) used to linearly interpolate between data points 12 (Chop after 2 decimal places) None of the above. -2.50x+0.20 -5.00x+2.00 -5.00x+2.00 5.00x-1.00 Consider the following data table: 2 Ti = 0 0.2 0.4 0.6 f(x) = 2.018 2.104 2.306 0.2 and 23 = 0.4, the value obtained at 2=0.3 is Using Lagrange linear interpolation...
3. Find the approximation of f(0.3) using Neville's method in the following table. XL -0.6 -0.1 0.2 0.8 f(x)] -0.54 0.90 1.22 2.23