Question

The diagram below represents an elevator used to lift concrete blocks to upper levels on a construction site. The belt travels at a velocity of 0.9 m/s and is inclined at 26° above the horizontal plane. Calculate the friction force and the coefficient of static friction between each block and the belt. Each block weights 16.5 kg. А NOT TO SCALE $300

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Answer 1

Img et u = dnia 2310 N $ 190 bro ef MO ort ve masing mgcoso si To mesine mgcoso block Above is the Img FBD diagram of a normal force 20 de at N. is the J grande frictional force

For go horizontal and Veltical eaim ( with respect N = 16.5 * 9.81x Costa ) to belt) mgsino = f and Coso =N mgloso • 16.5x9.81xsinao) =f f = 70.96 N N = 145,483 N WN he We also know, If ul is the static friction where 70,96 MX 145, 4483 le M = 0,488 and weal Concrete is, strong in compression Tension in to compression Tension - Tension Compressin So the vertical faces will first crack Stalting from the outside inside faces towards failure failure