Question

An experiment was conducted in which different dosages of a particular pesticide were administered to 5 groups of 5 mice. The 25 mice were females of similar age and condition. One group received no chemical. The basic response y was a measure of activity in the brain. It was postulated that brain activity would decrease with an increase in pesticide dosage. Use the given data to answer parts​ (a) and​ (b).Animal 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Dose, x (mg/kg body weight) 0.0 0.0 0.0 0.0 0.0 2.3

(a) Using the model Y; = Bo + B,x; +€;, i = 1, 2, ..., 25, find the least squares estimates of ßo and By. The least squares e(b) Construct an analysis-of-variance table in which the lack of fit and pure error have been separated. Determine if the lacComputed Complete the analysis-of-variance table below. Source of Sum of Degrees of Mean Variation Squares Freedom Square Reg

Make a conclusion about the hypothesis. Ho because the computed value of f in the table is the critical region at a = 0.05.

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Answer #1

a) n=25, Ei= 174.7 ,Eyis 210.9 E(Xi-) = 1056.306 Elyi- Isei 174.7 6.988 n 25 Eyi 2 10.9 8.436 n 25 V(X): < Ecxi - 5]? - 1056.The least-square estimate of bois 2:44 88 s] 10.5 The least-square estimate of bi is -0,343 b) To tost the lack of fit here tSou Sum of Square bf mean square compeeled f Resgression 124.69 1 124.69 Error 76.69 23 3.33 Lack of fit 50°13 3 1 : 71 0:48

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