a.)
rms value of current is given by,
Irms = Imax/sqrt(2)
from given graph, Imax = maximum value of current = 2 mA
then, Irms = 2/sqrt(2) = sqrt(2) mA
Irms = 1.414 mA = 1.414*10^-3 A
b.)
peak voltage will be:
Vmax = Imax*R
given, R = 5 kohm = 5*10^3 ohm
then, Vmax = (2*10^-3)*(5*10^3)
Vmax = 10 volts
c.)
from graph,
Time period of oscillation(T) = 4 ms = 4*10^-3 s
then, frequency(f) = 1/T
f = 1/(4*10^-3)
f = 250 Hz
"Let me know if you have any query."
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