Question

3. The current through a 8-uF capacitor is shown in the graph. Determine and graph the voltage across the capacitor, and power and energy stored in the capacitor. i(!) ma 2 4 6 8 10 (ms)

Answer 1

C = Sur A RUM 4 ---- cms) -2 - - - >> Ostems. inc.dy ve = fict) dt. V=0 Volt s. P=0 watt Energy = 0 Joules. 22tums 4. d t + o vo ( 46-35] Va (4-2) Vilts, Cam Lanner

Power V(t) ict) (7-2).4 Power = 264-2)..mw. Energy = Power & time = 2(+-2) xt Energy = a (+² at) MJ. 4 < t < 8 ms. initial voltage Volat t = 4 1 (2-2) 424 lat t= a = 1 volts VC) = s *ics dt + V VC+) = -1 (7-4) + ] VCt) = -5 +2 volts Scanned with CamScanner

Power = u(t) ilt) = (2-1)*(-2) Power = ± 4 mw Energy = Power x time Power x time (-4)*+ 8 tu loms Vila t=8mg = +2 las = 0 volts Ca sa volt) = icts dt+ 6 CamScanner

+(+-] vet) = ☆ (7-8) | VC+) = - +4 volts Power = vet) ilt) =( +4)(-4) Power = 2t - 16 mw Energy = P xt = (2+-16)(+) Energy - 2+² 16t us Ics 'Scanned with CamScanner

Volisa Vas 1 F . - -- - - - -- t(ms) in_ Voltage vs time mu Plt) - - . - 4 . - . - - - - - - . - - . tims) - 10 Power (mo) us time. 2() Energy is time Sanned with damscanner