Question

(26) A square loop of copper 3.0m across on each side lies on the table in front of you. A 0.4T magnetic field is oriented directly out of the table. The average resistance of the loop is 2.012. A. Over the course of 3.0 seconds, the magnetic field drops to zero. What emf is induced in the square loop? B. What is the magnitude of the current that will be induced in the loop? C. What is the direction of the magnetic field that will be induced in the loop? Explain how you know.

Answer 1

a = 3 m area ܚܢ then side of hoop magnetic field = B20.45 Resistance of the hoop so o 28 the loop Aa2=32=9m2 so flux through the Loop 8 BA= 0.449 Toma D 3.6 Tam 2 when mazgnetic field drops to 2010 fius passing through the Loop P" = Bazo A change of flux = dg = (3-0) = 3.67 m2 so according to Fanadang's Law emp induced in the eel-do Induced emf in the Loop e = 1020 Induced magnetic cuprente in the ts தனது ( A ) 200 P 3.6 1.2 V toop 1.2 ir efo 2 = 0.6A so ном Now Initially magnetic field oniented directly out of the page, and then after s see magnetic field droops to Beyo according to LOW Lena's a cuyment mitg induced in the Loop which opposes the change in magnetic field f.e compen Stout compensate the drops of magnetic field which will possible of magnetic field will induce "out of the page due to counter clockwise induced cul corrent e- Scanned with CamScanner