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cylinder of m= 0.53 kg and a radius 0.32 m is rotating around an axis through...

cylinder of m= 0.53 kg and a radius 0.32 m is rotating around an axis through its center. the cylinder’s moment of inertial is given by MR^2/2. The cylinder initially at rest. A force of 0.70n is then applied tangentially at the edge of the cylinder. How many radians will the cylinder rotate through in the first 2.5 seconds that the force is applied?

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Answer #1

2 - mai 4² 0.53x0.32² 2 Nm 2 hare / Torque Za af - (0.32m) (oto N) & IT = I x 0.224 =00291 kgru & NH 0.224 = 8.25 read /s² X-

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