Question

1. Complete a dihybrid cross between a pea plant (plant 1) with white flowers and wrinkled seeds with a plant (plant 2) with purple flowers and round seeds.
2. Fill in the Punnett square between Plant 1 and Plant 2. Plant 2 is heterozygous for flower color and homozygous for seed color.

What are the phenotypic ratios of the F1 generation?

Phenotypes:

purple flowers with round seeds:

purple flowers with wrinkled seeds:

white flowers with round seeds:

white flowers with wrinkled seeds:

Plant 1 is going across the top

Plant 2 is going down the side of chart

Answer 1

PLANT-2: → A ABB PLANT-I :> White flower wrinkled seeds - aabb Purple flower / Round seeds = (According to question, PLANT 2 is heterozygous flower color and homozygous for seed color coloor Parent la abb t AaBB Crametes > ab AB a B F » (A a B b (aaBb | aЬ Punnett 2 square AB AaBb Purple Round White Round Aa Bb Phenotypic Phenotypic ratio of fi generation 1 Purple flowers with round seeds a Purple Flowers with wrinkled seeds=0 White flowers with round seeds = White Flowers with wrinkled seeds = 0 |

F Aa Bb aaBb self fertilization F2 → Checker Board (Punnet Square) AB Ab a B ab ot a B AABB Aa Bb aaBB a a Bb. Purple, Round Purple, Round White, Round White, Round AaBb A abb a abb aabb ab Purple, Round Purple, wrinked white, Round White, carinkled Phenotypes :- Purple Flowers with round Seeds 3 Purple flowers with wrinkled seeds = 1/2 White flowers with round seeds - white flowers with our wrinkled seeds 8 3 8 i 8 The Phenotypes of Fz generation = 3: 1: 3 : 1