Question

b) Calculate moment of inertia of cross section about the z' axis that passes the center of area 0 as shown in the figure. (find center of area y first) YE d-3 in Sin S.S in s in c) ( D ) The max shear stress in a solid round shaft subjected only to torsion occurs: a) on principal planes b) on planes containing the axis of the shaft c) on the surface of the shaft d) only on planes perpendicular to the axis of the shaft e) at neutral axis ( 8 ) In an I-beam subjected to simple bending. The max bending stress occurs a) at the neutral axis b) in the web above neutral axis c) in the web below neutral axis d) at the top and bottom surface of the beam e) where the web joints the low flange. Indicate the stress magnitude and direction on the cross-section due to torsion, bending, transverse shear 6 T 2003

Answer 1

Please refer the following image for the solution.

Solution 2 C2 2-3in dyz 1 dykt 5.5in 1) y=3.678 in 50 4 LA Let the artea total Area A (in) divided into two parts and 2. y 'cin) YxA Cin) 8/2=4 part 8x5= 40 160 38.8773 5.5 Tx3- 7.0686 160 - 38.8773 40-7.0686 ΣΑ ..y Σγ'Α --Y = 3.678 in By parallel axis theorem Iz = Izt Ady dy. - Yi-Y = 4-3.678 = 0.322 in dy = 72- y = 5.5-3.678 = 1.822 in dager part Area, A Cin²) dy cin) Axdý cine Iz cint) Iz Ady ² 4.14736 (5233) =213.33 213.3374.14736 =217.477 23.4655 2 139= 3.976 3.976+ 23.4655=27.4415 40 7.0686 0.322 11.822 .. reeds HORBA 123 i. Iz= Iz, - Izz = 217.477-27.4415 Iz = 190 int