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c) The Activated Sludge Process of Question b is designed for effluent BOD5 of 20 mg/1....
c) The Activated Sludge Process of Question b is designed for effluent BOD5 of 20 mg/1....
c) The Activated Sludge Process of Question b is designed for effluent BOD5 of 20 mg/1. However, due to faulty functioning of SST, some VSS is escaping with the treated effluent. Due to this, BOD5 of the effluent is estimated as 28 mg/L. Considering that 66% of VSS is biodegradable, estimate the VSS escaping in the effluent. d) Why biogas composition usually is 55% methane?
a) Due to faulty functioning of the secondary settling tank (SST), some VSS is washed out...
a) Due to faulty functioning of the secondary settling tank (SST), some VSS is washed out with the effluent. Highlight possible effects of VSS washout. b) Activated Sludge Process is operating with . of 11.76 days and F/M of 0.3 d. For Y of 0.5 and k, of 0.05 d', estimate the effluent BOD5 if s, is 200 mg/L. c) The Activated Sludge Process of Question b is designed for effluent BOD5 of 20 mg/l. However, due to faulty functioning...
2. A completely mixed activated sludge process is designed to treat 20,000 m/d of domestic wastew...
2. A completely mixed activated sludge process is designed to treat 20,000 m/d of domestic wastewater having a BODs concentration of 250 mg/L following primary treatment. The NPDES permit requirement for effluent BODs and TSS is 20 mg/L for each. The biokinetic parameters have beern established as: yield 0.6, k 5/d, K-60 mg/L, and kd 0.06/d. The MLVSS concentration in the aeration tank is to be maintained at 3000 mg/L and the ratio of VSS/TSS is 0.75. Assume that the...
just part e please Activated sludge design A completely mixed activated sludge process is designed to...
just part e please
Activated sludge design A completely mixed activated sludge process is designed to treat 20,000 m/day of domestic wastewater having a BODs concentration of 250 mg/L following primary treatment. The NPDES permit requires that the effluent BOD, and TSS concentra- tions not exceed 20 mg/L on an annual basis. The following biokinetic coefficients are to be used in the design of the process: Y = 0.6 mg VSS/mg BODs, k = 5d"! Ks = 60 mg/L BODs,...
Question 2 A complete mix activated sludge process is to be used for biological treatment. Assume...
Question 2 A complete mix activated sludge process is to be used for biological treatment. Assume the following for the activated sludge process: • Plant influent BODs of 156 mg/L • Sludge age is 8 days Biomass yield (Y) of 0.54 kg biomass / kg BOD • Endogenous decay rate (kd) = 0.05 day! • Ks=10 g BOD/m3 Biomass concentration (X) of 2700 mg/L • recycle biomass concentration (Xr) of 12,000 mg/L The fresh flow rate treated is 1000 m²/day...
Question 2: (Marks 10) Wastewater with flow rate of 10,000 mº/d containing 280 mg/L of ethanolamine...
Question 2: (Marks 10) Wastewater with flow rate of 10,000 mº/d containing 280 mg/L of ethanolamine (C2H7NO) is to be treated by Activated Sludge Process (ASP). a) Estimate the Total Oxygen Demand (TOD) and Nitrogenous Oxygen Demand (NOD) of wastewater. b) Assuming that the COD removal rate in the aeration tank is 1.2 kg COD/mºday at 20°C, estimate the volume of the aeration tank required to achieve the effluent standard of 20 mg/L of COD.
CIEG 328 HOMEWORK7 Homework 7 (Suspended growth) Due: 4/112019 Design an activated sludge biologi...
CIEG 328 HOMEWORK7 Homework 7 (Suspended growth) Due: 4/112019 Design an activated sludge biological treatment system for a typical medium-strength domestic wastewater with a design daily flow of 2.9 million gallons per day. Assume the plant effluent criteria are 10/10/1" This means that the plant must produce an effuent with average BODS and TSS concentrations of 10 mg/Leach year round, and an effluent ammonia concentration of 1 mg/L as N during the winter months. The layout of the plant will...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of raw wastewater to be treated is 20 MGD in the design year, the dissolved BODs is 380 mg/L, and SS is 360 mg/L. The wastewater generated by the sludge treatment process is about 4 MGD with the dissolved BODs being 1800 mg/L, and SS being 1200 mg/L, and will be returned to the wet well in the pumping station at the beginning of the...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...
c) The Activated Sludge Process of Question b is designed for effluent BOD5 of 20 mg/1. However, due to faulty functioning of SST, some VSS is escaping with the treated effluent. Due to this, BOD5 of the effluent is estimated as 28 mg/L. Considering that 66% of VSS is biodegradable, estimate the VSS escaping in the effluent. d) Why biogas composition usually is 55% methane?
a) Due to faulty functioning of the secondary settling tank (SST), some VSS is washed out with the effluent. Highlight possible effects of VSS washout. b) Activated Sludge Process is operating with . of 11.76 days and F/M of 0.3 d. For Y of 0.5 and k, of 0.05 d', estimate the effluent BOD5 if s, is 200 mg/L. c) The Activated Sludge Process of Question b is designed for effluent BOD5 of 20 mg/l. However, due to faulty functioning...
2. A completely mixed activated sludge process is designed to treat 20,000 m/d of domestic wastewater having a BODs concentration of 250 mg/L following primary treatment. The NPDES permit requirement for effluent BODs and TSS is 20 mg/L for each. The biokinetic parameters have beern established as: yield 0.6, k 5/d, K-60 mg/L, and kd 0.06/d. The MLVSS concentration in the aeration tank is to be maintained at 3000 mg/L and the ratio of VSS/TSS is 0.75. Assume that the...
just part e please
Activated sludge design A completely mixed activated sludge process is designed to treat 20,000 m/day of domestic wastewater having a BODs concentration of 250 mg/L following primary treatment. The NPDES permit requires that the effluent BOD, and TSS concentra- tions not exceed 20 mg/L on an annual basis. The following biokinetic coefficients are to be used in the design of the process: Y = 0.6 mg VSS/mg BODs, k = 5d"! Ks = 60 mg/L BODs,...
Question 2 A complete mix activated sludge process is to be used for biological treatment. Assume the following for the activated sludge process: • Plant influent BODs of 156 mg/L • Sludge age is 8 days Biomass yield (Y) of 0.54 kg biomass / kg BOD • Endogenous decay rate (kd) = 0.05 day! • Ks=10 g BOD/m3 Biomass concentration (X) of 2700 mg/L • recycle biomass concentration (Xr) of 12,000 mg/L The fresh flow rate treated is 1000 m²/day...
Question 2: (Marks 10) Wastewater with flow rate of 10,000 mº/d containing 280 mg/L of ethanolamine (C2H7NO) is to be treated by Activated Sludge Process (ASP). a) Estimate the Total Oxygen Demand (TOD) and Nitrogenous Oxygen Demand (NOD) of wastewater. b) Assuming that the COD removal rate in the aeration tank is 1.2 kg COD/mºday at 20°C, estimate the volume of the aeration tank required to achieve the effluent standard of 20 mg/L of COD.
CIEG 328 HOMEWORK7 Homework 7 (Suspended growth) Due: 4/112019 Design an activated sludge biological treatment system for a typical medium-strength domestic wastewater with a design daily flow of 2.9 million gallons per day. Assume the plant effluent criteria are 10/10/1" This means that the plant must produce an effuent with average BODS and TSS concentrations of 10 mg/Leach year round, and an effluent ammonia concentration of 1 mg/L as N during the winter months. The layout of the plant will...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of raw wastewater to be treated is 20 MGD in the design year, the dissolved BODs is 380 mg/L, and SS is 360 mg/L. The wastewater generated by the sludge treatment process is about 4 MGD with the dissolved BODs being 1800 mg/L, and SS being 1200 mg/L, and will be returned to the wet well in the pumping station at the beginning of the...
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