Question

1.) The method to bring the electrons to a specific velocity Ŭ is described in the intro- duction. Determine the exiting velocity of the electrons as it leaves the accelerating voltage AV region. Assume the electron starts from rest, travels the whole region, and conserves energy (AK + AU = 0). Hint: Recall the potential energy of a charged particle. 2.) Prepare a diagram of the position of charged particle in a magnetic field Ę, travelling at velocity ✓ perpendicular to the magnetic field. From this, derive an expression for housing Eqn. 1 and 2. Hint: Make sure you have drawn the magnetic field direction pointing into or out of your page, while the electron travels in the plane of the page. 3.) Quantities which are directly adjustable in this lab are the accelerating voltage AV, and the magnetic field B while an observed/measured quantity is the radius of the electron's path r. Rearrange the expression determined above in such a way that the ration can be determined from the slope of a graph. This will be the governing equation you will use for the lab. Hint: Think about the graph and the variables you want on each of the axes.

Answer 1

Celectron) Here it is mentioned that an e- is accelerated by potential differena su the potential energy of charged partich is given by su= - ev where v- potential differece Also kinetic energy = AK = 1 meu? using Akt Du from ques.equn 1 and ② I meu? - eV = 0 Ime uz = ev 2ev 2ev m Ans m (b) Here e- is travelling in the magnetic field B o outward the page. in magnetic field the e will ravel in circle So using centrifugal force we get muz q UB ma r qB q m Any 4 Br

using (3 and (4) potential we get velocity in terms of 2qV also we have ทา Br q JE Izqv . I putting ū from m m Br above MI 2 m Jav. I Br q m = 2 V B²2 -squaring both side Here q = е e m 2 V Aus B2,2 B² e further . if will take I as y 1 2v m ra then we can say Here slope = tan olm.