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he telecast? 10 # 3 Among the 24 invoices, 4 contain errors while the others do not. If we randomly check 3 of these invoices
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Answer #1

since there are total 24 invoices

and 4 contain errors

we can draw 3 invoices from 24 invoices in 24C3 ways

while we can draw 3 error containing invoices in 4C3 ways so

required probability is given by

P=\frac{\binom{4}{3}}{\binom{24}{3}}=\frac{4*3*2}{22*23*24}=\frac{1}{506}

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