Define the standard random variable Z as
where X denotes the amount of compound in milligrams
For X=9.65 the Z score is
For X=9.95 the Z score is
Hence, using Normal table we have the required probability as
So the probability that the vial is within acceptable range is 0.4207
Please note, the question is asking what is the probabilty that you select a vial that...
You work for a pharmaceuticals company as a statistical process analyst. Your job is to analyze processes and make sure they are in statistical control. In one process, a machine is supposed to add 9.8 milligrams of a compound to a mixture in a vial. (Assume this process can be approximated by a normal distribution with a standard deviation of 0.05.) The acceptable range amounts of the compound added is 9.65 milligrams to 9.95 milligrams, inclusive. Because of an error...
You work for a pharmaceuticals company as a statistical process analyst. Your job is to analyze processes and make sure they are in statistical control. In one process, a machine is supposed to add 9.8 milligrams of a compound to a mixture in a vial. (Assume this process can be approximated by a normal distribution with a standard deviation of 0.05.) The acceptable range amounts of the compound added is 9.65 milligrams to 9.95 milligrams, inclusive. Because of an error...
I am a bit lost, totally forgot how to do this. You work for a pharmaceuticals company as a statistical process analyst. Your job is to analyze processes and make sure they are in statistical control. In one process, a machine is supposed to add 9.8 milligrams of a compound to a mixture in a vial. (Assume this process can be approximated by a normal distribution with a standard deviation of 0.05.) The acceptable range amounts of the compound added...
Assume the machine shifts and is filling the vials with a mean amount of 9.96 milligrams and a standard deviation of 0.05 milligrams you select 5 vials and find the mean amount compounded added. What is the probability that you select a sample of five vial that has a mean that is within the acceptable range? What formula is being used for this? I have the answer(0.3264) I don't understand how they are getting this answer and how they are...