Question

The lifespan of the Ebola virus on flat dry surfaces has a normal distribution with μ=926.6μ=926.6 minutes and σ=78.8σ=78.8 minutes. You monitor a random sample of size n=97.

What is the mean of the distribution of sample means?
μ¯x=μx¯=

What is the standard deviation of the distribution of sample means?
(Report answer accurate to 2 decimal places.)
σ¯x=σx¯=

Answer 1

Ans U= 926.6, o= 78.8, ne 97 with mean X "N(4,02 Central limit theorem (CLT) If x follow normal distribution H. and standard deviation of then sampling distribution of x (*) will follow normal distribution with and standard deviation of ) mean 4x = 4 3719 6 Mean of distribution of sample mean- 나: H = 926.6 Hv= 926.6 (2) Stondord deviation of the distribution of sample meant ох 6/LE = 78.8 N 97 8.00 of 8.00