Question

Learning Goal: To calculate torsional deformation and shear stress due to an applied force in a door handle design. A locked door handle is composed of a solid circular shaft AB with a diameter fb = 105 mm and a flat plate BC with a force P = 76 N applied at point C as shown. Let c = 543 mm, d = 125 mm, and e = 145 mm. (Treat the handle as if it were a cantilever beam.) m B X

Answer 1

maximum shear stress at sec hom 'mom' is gren as 2 2 man 2 ()+7 (186306-7)= ( 48.3831 do do"-di" 210.1762 do do"-di' 863.8377 0.135 do do"-dih (0.135)4-di" di = 115.16 mm vi = 57.58 mm inner radius of hollow shaft is 57. 58 mm. Part-C 6 Callow = 149 MPa = 149 x lo lo N do =0.135m di = 0.J1516m m2 = 1 os X 32 32 て、 Tor - let p be maximum permissible load. fos J = I. (do4 d: ") = [Co.135)" (0.11516)") = 1.53422 x1ő my P (0.543)* (0.135/2) (2388.999) P. la 53422 * 10.5 P. (e+d) P(0.145+0.125) (0.27) P. ( do--di“) Co.135) " (0.11516)*] = 7.6711 x 16 J 3/2 cm) man man -6 4 I 7 64 64 ob (m)man Iman 0.27. p. ?: (0:135) - (2375.8) I ma maximum shear stress is sheas shess is given ob T² 7.6711 x 10-6 as- 2 2 Tman ( + (148 x10*)= (2375-81) (2368.999p) + (P) 55.84 63 KN man Force CamScanner that can be applied to handle is 55. 8463 KN

P P=76N d- 0.125m - Solni force on a door is shifted to door is shi fled to cantilever beam, have effect of combination & bending load 'p' and Torque y magnitude 'Pic'. im C=0.543 m PC-T e: 0.145m b = 0.10 sm (diame les q handle free body diagram & infinisimally small section at m-m. moment at section (m-m) Pod=764 0.125 m = 9.5 N-m. e d- 3 Part-A که جم 06 = Ob = 0 63 32 M. 32x9.5 83. 5903 K Pa. a Co.105)3 (1) 16 T 16% 41.268 = 181.5581 k Pa. T= 76x 0.543 A Co.105)3 T= 41.268 NAM maximum sheas shoess at section 'm-m' is given as . Eman Sol47² 83,5903 186.3067 kPa ab13 ob (941 = (6335903) 4 (101.558) !. maximum sheas shess at section 'mam is 186.30 67 kPa. Part -B (Iman = 186.3067 K Pa do = 135mm = 0.135m. let di be diameter shaft. 8 inner JE À (do?-d;") 8o = do 2 32 of てこ To do 66 - 41.266 x (1/2) I (dold;") (210.1962)do do" din J m2 32 I - A (dou_d;") I Joman = do 64 бр M. Yman N 1 9.5*(0/2) (dold;") (96.7662) do do"-di" 1 m2 64 is Scanned with CamScanner