Question

Learning Goal: To calculate torsional deformation and shear stress due to an applied force in a door handle design. A locked door handle is composed of a solid circular shaft AB with a diameter of b = 101 mm and a flat plate BC with a force P = 77 N applied at point C as shown. Let c = 473 mm, d = 126 mm, and e = 148 mm (Treat the handle as if it were a cantilever beam.) m B

Answer 1

Crinen daimeter b=10mm 0101m P = 770 (- 473 = 0.473m - d=126mm - 0.126m et 148 mm= o.148M Manimum shen es mess equation of Torsion て IZ T= PAC T How T= 77x0.473 J = 7 / 42 D4 て PXC How 72 e b4 D=db= 0.10lm T = 16 PRC T D3 T= 16x 77 x 0,473 Txo.1013 T= 180.05 x 103 pa T= 180.035 kPa 21

part innen deumeter di= ? do = 132mn= 0.132m Ć T Thellow 4 . de 2. T=PxC Ihollow = I (dot-d;4) 32 PXC С do X (do" -di") 2 32 в Рус x do doo T 32 (dot - di 1:4) で dot-dit 16 PxC doo T て 4. dit = do 16 Pacado ↑ XT 4 di = 0.132 16x77X0.473 x 0.132 T X 180.035x 103 dit = 1.67595810-4 di = 0.11381m di= 113.81 mm

part marximum force ? Tallow | 49 м Pa = 14 хора T J 2 Tallow Рx р. Л” 32 СД4 2 Сс 0:4 13 Tallow : 16 РКС (alo = 1410 6 пр3 Dao'lolm 14 – ко 6 — 16xpx p. 493 л хъ: 1013 .. P= 62 - 91 к 10° 2 Р - С2 . 89 км Ar
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