from triangle xyz
cos 30 = r / L/2
r = L cos 30 / 2
and
from triangle xvw
L = H / sin 30
where , H = R + R cos 30
net torque about center of mass of stick
N L = mgr
N = mgr / L
N = mgL sin 30 cos 30 / 2R ( 1 + cos 30)
where, R = 15/ 2 = 0.075 m
N = 0.240 * 9.8 * 0.395 * cos 30 sin 30 / 2 * 0.075 ( 1 + cos 30)
N = 1.437 Newtons
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Fx = N sin 30
Fx = 0.7186 N
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Fy = mg - N cos 30
Fy = 0.240 * 9.8 - 1.437 cos 30
Fy = 1.1075 N
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